x^2+16x-341=0

Solution for x^2+16x-341=0 equation:

x^2+16x-341=0

a = 1; b = 16; c = -341;
Δ = b2-4ac
Δ = 162-4·1·(-341)
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-18\sqrt{5}}{2*1}=\frac{-16-18\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+18\sqrt{5}}{2*1}=\frac{-16+18\sqrt{5}}{2}
$